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How do I access the Object.prototype method in the following logic?

Hello Guys, How are you all? Hope You all Are Fine. Today we are going to learn How do I access the Object.prototype method in the following logic? in javascript. So Here I am Explain to you all the possible methods here.

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How do I access the Object.prototype method in the following logic ?

  1. How do I access the Object.prototype method in the following logic ?

    do I access the Object.prototype method in the following logic It seems like this would also work:
    key in entries
    since that will return a boolean on whether or not the key exists inside the object?

  2. How do I access the Object.prototype method in the following logic ?

    do I access the Object.prototype method in the following logic It seems like this would also work:
    key in entries
    since that will return a boolean on whether or not the key exists inside the object?

Method 1

You can access it via Object.prototype:

Object.prototype.hasOwnProperty.call(obj, prop);

That should be safer, because

  • Not all objects inherit from Object.prototype
  • Even for objects which inherit from Object.prototype, the hasOwnProperty method could be shadowed by something else.

Of course, the code above assumes that

  • The global Object has not been shadowed or redefined
  • The native Object.prototype.hasOwnProperty has not been redefined
  • No call own property has been added to Object.prototype.hasOwnProperty
  • The native Function.prototype.call has not been redefined

If any of these does not hold, attempting to code in a safer way, you could have broken your code!

Another approach which does not need call would be

!!Object.getOwnPropertyDescriptor(obj, prop);

Method 2

It seems like this would also work:

key in entries

since that will return a boolean on whether or not the key exists inside the object?

Summery

It’s all About this article. Hope all method helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which method worked for you? Thank You.

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