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How to create a Bruteforce password cracker for alphabetical and alphanumerical passwords?

Hello Guys, How are you all? Hope You all Are Fine. Today We Are Going To learn about How to create a Bruteforce password cracker for alphabetical and alphanumerical passwords in Python. So Here I am Explain to you all the possible Methods here.

Without wasting your time, Let’s start This Article.

How to create a Bruteforce password cracker for alphabetical and alphanumerical passwords?

  1. How to create a Bruteforce password cracker for alphabetical and alphanumerical passwords?

    Here's a naiive brute force method that will guess numbers (string.digits) and lower case letters (string.ascii_lowercase).

  2. create a Bruteforce password cracker for alphabetical and alphanumerical passwords

    Here's a naiive brute force method that will guess numbers (string.digits) and lower case letters (string.ascii_lowercase).

Method 1

Here’s a naiive brute force method that will guess numbers (string.digits) and lower case letters (string.ascii_lowercase). You can use itertools.product with repeat set to the current password length guessed. You can start at 1 character passwords (or whatever your lower bound is) then cap it at a maximum length too. Then just return when you find the match.

import itertools
import string

def guess_password(real):
    chars = string.ascii_lowercase + string.digits
    attempts = 0
    for password_length in range(1, 9):
        for guess in itertools.product(chars, repeat=password_length):
            attempts += 1
            guess = ''.join(guess)
            if guess == real:
                return 'password is {}. found in {} guesses.'.format(guess, attempts)
            # uncomment to display attempts, though will be slower
            #print(guess, attempts)

print(guess_password('abc'))

Output

a 1
b 2
c 3
d 4
...
aba 1369
abb 1370
password is abc. found in 1371 guesses.

Method 2

One possible option which would preserve almost exactly your current code is to convert to base 36 with the following “digits”: 0-9a-z. This will give you every possible alpha-numeric combination for n characters if you search in range(36**n).

def baseN(num, b=36, numerals="0123456789abcdefghijklmnopqrstuvwxyz"):
    return ((num == 0) and numerals[0]) or (baseN(num // b, b, numerals).lstrip(numerals[0]) + numerals[num % b])

You can then loop through numbers as in your example:

>>> for i in range(10000, 10005):
...     print(baseN(i).zfill(5))
...
007ps
007pt
007pu
007pv
007pw

To get all 3-letter possibilities, you can loop as follows:

for i in range(36**3):
    possible = baseN(i).zfill(3)

Conclusion

It’s all About this issue. Hope all Methods helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which Method worked for you? Thank You.

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