Hello Guys, How are you all? Hope You all Are Fine. Today We Are Going To learn about **How to find cube root using Python?** **in Python**. So Here I am Explain to you all the possible Methods here.

Without wasting your time, Let’s start This Article.

Table of Contents

## How to find cube root using Python?

**How to find cube root using Python?**This takes the cube root of

`x`

, rounds it to the nearest integer, raises to the third power, and finally checks whether the result equals`x`

.**find cube root using Python**This takes the cube root of

`x`

, rounds it to the nearest integer, raises to the third power, and finally checks whether the result equals`x`

.

## Method 1

You could use `x ** (1. / 3)`

to compute the (floating-point) cube root of `x`

.

The slight subtlety here is that this works differently for negative numbers in Python 2 and 3. The following code, however, handles that:

def is_perfect_cube(x): x = abs(x) return int(round(x ** (1. / 3))) ** 3 == x print(is_perfect_cube(63)) print(is_perfect_cube(64)) print(is_perfect_cube(65)) print(is_perfect_cube(-63)) print(is_perfect_cube(-64)) print(is_perfect_cube(-65)) print(is_perfect_cube(2146689000)) # no other currently posted solution # handles this correctly

This takes the cube root of `x`

, rounds it to the nearest integer, raises to the third power, and finally checks whether the result equals `x`

.

The reason to take the absolute value is to make the code work correctly for negative numbers across Python versions (Python 2 and 3 treat raising negative numbers to fractional powers differently).

## Method 2

The best way is to use simple math

>>> a = 8 >>> a**(1./3.) 2.0

**EDIT**

For Negative numbers

>>> a = -8 >>> -(-a)**(1./3.) -2.0

Complete Program for all the requirements as specified

x = int(input("Enter an integer: ")) if x>0: ans = x**(1./3.) if ans ** 3 != abs(x): print x, 'is not a perfect cube!' else: ans = -((-x)**(1./3.)) if ans ** 3 != -abs(x): print x, 'is not a perfect cube!' print 'Cube root of ' + str(x) + ' is ' + str(ans)

**Conclusion**

It’s all About this issue. Hope all Methods helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which Method worked for you? Thank You.

**Also, Read**