# How to fix Index: invalid index to scalar variable

Hello Guys, How are you all? Hope You all Are Fine. Today We Are Going To learn about How to fix Index: invalid index to scalar variable in Python. So Here I am Explain to you all the possible Methods here.

## How to fix Index: invalid index to scalar variable?

1. How to fix Index: invalid index to scalar variable?

You are trying to index into a scalar (non-iterable) value:
`[y[1] for y in y_test] # ^ this is the problem`

2. fix Index: invalid index to scalar variable

You are trying to index into a scalar (non-iterable) value:
`[y[1] for y in y_test] # ^ this is the problem`

## Method 1

You are trying to index into a scalar (non-iterable) value:

```[y[1] for y in y_test]
#  ^ this is the problem
```

When you call `[y for y in test]` you are iterating over the values already, so you get a single value in `y`.

Your code is the same as trying to do the following:

```y_test = [1, 2, 3]
y = y_test[0] # y = 1
print(y[0]) # this line will fail
```

I’m not sure what you’re trying to get into your results array, but you need to get rid of `[y[1] for y in y_test]`.

If you want to append each y in y_test to results, you’ll need to expand your list comprehension out further to something like this:

```[results.append(..., y) for y in y_test]
```

Or just use a for loop:

```for y in y_test:
results.append(..., y)```

## Method 2

Basically, `1` is not a valid index of `y`. If the visitor is comming from his own code he should check if his `y` contains the index which he tries to access (in this case the index is `1`).

## Conclusion

It’s all About this issue. Hope all Methods helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which Method worked for you? Thank You.