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[Solved] Index Error: list index out of range (Python)

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Index Error: list index out of range (Python) in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Index Error: list index out of range (Python) Error Occurs?

Today I get the following error Index Error: list index out of range (Python) in python.

How To Solve Index Error: list index out of range (Python) Error ?

  1. How To Solve Index Error: list index out of range (Python) Error ?

    To Solve Index Error: list index out of range (Python) Error If you have a list with 53 items, the last one is thelist[52] because indexing starts at 0.

  2. Index Error: list index out of range (Python)

    To Solve Index Error: list index out of range (Python) Error If you have a list with 53 items, the last one is thelist[52] because indexing starts at 0.

Solution 1


If you have a list with 53 items, the last one is thelist[52] because indexing starts at 0.

IndexError

  • Attribution to Real Python: Understanding the Python Traceback – IndexError

The IndexError is raised when attempting to retrieve an index from a sequence (e.g. listtuple), and the index isn’t found in the sequence. The Python documentation defines when this exception is raised:

Raised when a sequence subscript is out of range. (Source)

Here’s an example that raises the IndexError:

test = list(range(53))
test[53]

---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
<ipython-input-6-7879607f7f36> in <module>
      1 test = list(range(53))
----> 2 test[53]

IndexError: list index out of range

The error message line for an IndexError doesn’t provide great information. See that there is a sequence reference that is out of range and what the type of the sequence is, a list in this case. That information, combined with the rest of the traceback, is usually enough to help quickly identify how to fix the issue.

Solution 2

Yes,

You are trying to access an element of the list that does not exist.

MyList = ["item1", "item2"]
print MyList[0] # Will work
print MyList[1] # Will Work
print MyList[2] # Will crash.

Have you got an off-by-one error?

Summery

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