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[Solved] Popen error: [Errno 2] No such file or directory

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Popen error: [Errno 2] No such file or directory in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Popen error: [Errno 2] No such file or directory Error Occurs?

Today I get the following error Popen error: [Errno 2] No such file or directory in python.

How To Solve Popen error: [Errno 2] No such file or directory Error ?

  1. How To Solve Popen error: [Errno 2] No such file or directory Error ?

    To Solve Popen error: [Errno 2] No such file or directory Error Try add an extra parameter shell=True to the Popen call.

  2. Popen error: [Errno 2] No such file or directory

    To Solve Popen error: [Errno 2] No such file or directory Error Try add an extra parameter shell=True to the Popen call.

Solution 1

Try add an extra parameter shell=True to the Popen call.

Solution 2

Just a note. shell=True was likely the correct solution to the o.p., since they did not make the following mistake, but you can also get the “No such file or directory” error if you do not split up your executable from its arguments.

import subprocess as sp, shlex
sp.Popen(['echo 1']) # FAILS with "No such file or directory"
sp.Popen(['echo', '1']) # SUCCEEDS
sp.Popen(['echo 1'], shell=True) # SUCCEEDS, but extra overhead
sp.Popen(shlex.split('echo 1')) # SUCCEEDS, equivalent to #2

Without shell=True, Popen expects the executable to be the first element of args, which is why it fails, there is no “echo 1” executable. Adding shell=True invokes your system shell and passes the first element of args to the shell. i.e. for linux, Popen(['echo 1'], shell=True) is equivalent to Popen('/bin/sh', '-c', 'echo 1') which is more overhead than you may need. See Popen() documentation for cases when shell=True is actually useful.

Summery

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