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[Solved] Python ‘AttributeError: ‘function’ object has no attribute ‘min”

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Python ‘AttributeError: ‘function’ object has no attribute ‘min” in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Python ‘AttributeError: ‘function’ object has no attribute ‘min” Error Occurs?

Today I get the following error Python ‘AttributeError: ‘function’ object has no attribute ‘min” in python.

How To Solve Python ‘AttributeError: ‘function’ object has no attribute ‘min” Error ?

  1. How To Solve Python 'AttributeError: 'function' object has no attribute 'min'' Error ?

    To Solve Python 'AttributeError: 'function' object has no attribute 'min'' Error I encountered a similar error when I called timezone.now instead of timezone.now()

  2. Python 'AttributeError: 'function' object has no attribute 'min''

    To Solve Python 'AttributeError: 'function' object has no attribute 'min'' Error I encountered a similar error when I called timezone.now instead of timezone.now()

Solution 1


If this line

new_x = np.linspace(x.min(), x.max(), new_length)

is generating the error message

AttributeError: 'function' object has no attribute 'min'

then x is a function, and functions (in general) don’t have min attributes, so you can’t call some_function.min(). What is x? In your code, you’ve only defined it as

x=var

I’m not sure what var is. var isn’t a default builtin in Python, but if it’s a function, then either you’ve defined it yourself for some reason or you’ve picked it up from somewhere (say you’re using Sage, or you did a star import like from sympy import * or something.)

[Update: since you say you’re “using PyLab”, probably var is numpy.var which has been imported into scope at startup in IPython. I think you really mean “using IPython in --pylab mode.]

You also define x1 and y1, but then your later code refers to x and y, so it sort of feels like this code is halfway between two functional states.

Now numpy arrays do have a .min() and .max() method, so this:

>>> x = np.array([0.1, 0.3, 0.4, 0.7])
>>> y = np.array([0.2, 0.5, 0.6, 0.9])
>>> new_length = 25
>>> new_x = np.linspace(x.min(), x.max(), new_length)
>>> new_y = sp.interpolate.interp1d(x, y, kind='cubic')(new_x)

would work. Your test data won’t because the interpolation needs at least 4 points, and you’d get

ValueError: x and y arrays must have at least 4 entries

Solution 2

I encountered a similar error when I called timezone.now instead of timezone.now(). I then tried to format the DateTime value that I was expecting. But it wasn’t a DateTime; it was a function. This resulted in an error message about ‘Month’ not being an attribute of ‘function’.

The fix was to simply add the parentheses after now. This called the now function and returned its result, instead of returning the now function object itself.

Silly mistake, I know. But not easy to troubleshoot.

Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.

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