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[Solved] Python error: FileNotFoundError: [Errno 2] No such file or directory

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Python error: FileNotFoundError: [Errno 2] No such file or directory in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Python error: FileNotFoundError: [Errno 2] No such file or directory Error Occurs?

Today I get the following error Python error: FileNotFoundError: [Errno 2] No such file or directory in python.

How To Solve Python error: FileNotFoundError: [Errno 2] No such file or directory Error ?

  1. How To Solve Python error: FileNotFoundError: [Errno 2] No such file or directory Error ?

    To Solve Python error: FileNotFoundError: [Errno 2] No such file or directory Error Non-absolute paths specify locations in relation to current working directory (CWD, see os.getcwd).

  2. How To Solve Python error: FileNotFoundError: [Errno 2] No such file or directory Error ?

    To Solve Python error: FileNotFoundError: [Errno 2] No such file or directory Error Non-absolute paths specify locations in relation to current working directory (CWD, see os.getcwd).

Solution 1

You are not giving the full path to a file to the open(), just its name – a relative path.

Non-absolute paths specify locations in relation to current working directory (CWD, see os.getcwd).

You would have to either os.path.join() correct directory path to it, or os.chdir() to the directory that the files reside in.

Also, remember that os.path.abspath() can’t deduce the full path to a file just by it’s name. It will only prefix its input with the path of the current working directory, if the given path is relative.

Looks like you are forgetting to modify the the file_array list. To fix this, change the first loop to this:

file_array = [os.path.join(prefix_path, name) for name in file_array]

Let me reiterate.

This line in your code:

file_array = [os.path.abspath(f) for f in os.listdir(prefix_path) if f.endswith('.txt')]

is wrong. It will not give you a list with correct absolute paths. What you should’ve done is:

import os
import glob

prefix_path = ("C:/Users/mpotd/Documents/GitHub/Python-Sample-"    
               "codes/Mayur_Python_code/Question/wx_data/")
target_path = open('MissingPrcpData.txt', 'w')
file_array = [f for f in os.listdir(prefix_path) if f.endswith('.txt')]
file_array.sort() # file is sorted list

file_array = [os.path.join(prefix_path, name) for name in file_array]

for filename in file_array:
     log = open(filename, 'r')

Solution 2

You are using relative path where you should be using an absolute one. It’s a good idea to use os.path to work with file paths. Easy fix for your code is:

prefix = os.path.abspath(prefix_path) 
file_list = [os.path.join(prefix, f) for f in os.listdir(prefix) if f.endswith('.txt')]

Note that there are some other issues with your code:

  1. In python you can do for thing in things. You did for thing in range(len(things)) it’s much less readable and unnecessary.
  2. You should use context managers when you open a file.

Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.

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