Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error **SyntaxError invalid token** **in python**. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

Table of Contents

## How SyntaxError invalid token Error Occurs?

Today I get the following error **SyntaxError invalid token** **in python**.

## How To Solve SyntaxError invalid token Error ?

**How To Solve SyntaxError invalid token Error ?**To Solve SyntaxError invalid token Error

`04`

is a valid integer literal in Python 2.x. It is interpreted as a base-8 (octal) number.`09`

would be an invalid token as well, since`9`

is not a valid octal digit.**SyntaxError invalid token**To Solve SyntaxError invalid token Error

`04`

is a valid integer literal in Python 2.x. It is interpreted as a base-8 (octal) number.`09`

would be an invalid token as well, since`9`

is not a valid octal digit.

## Solution 1

In Python 3, leading zeros are not allowed on numbers. E.g:

05 0123

Etc. are not allowed, but should be written as `5`

and `123`

instead.

In Python 2, however, the leading zero signifies that the number is an *octal number* (base eight), so `04`

or `03`

would mean `4`

and `3`

in octal, respectively, but `08`

would be invalid as it is not a valid octal number.

In Python 3, the syntax for octals changed to this:

0o10 0o4

(As well as allowing other bases such as binary and hexadecimal using the `0b`

or `0x`

prefixes.)

As for your other question, a token in Python is the way the Python interpreter splits up your code into chunks, so that it can understand it Here, when the tokenizer tries to split up your code it doesn’t expect to see the zero there and so throws an error.

I would suggest (similarly to the other answers) that you drop the leading zero (`(2016,4,3)`

) or represent these using strings (`("2016","04","03")`

).

## Solution 2

`04`

is a valid integer literal in Python 2.x. It is interpreted as a base-8 (octal) number. `09`

would be an invalid token as well, since `9`

is not a valid octal digit.

In Python 3, the form of octal literals changed. A leading zero alone is no longer valid; you need to explicitly specify the base. For example, `0o12`

is equal to `10`

.

In your case, you probably want to just drop the leading 0: `a = (2016, 4, 3)`

. Leading zeros could be added to the string representation of your tuple when necessary, rather than trying to store them explicitly.

**Summery**

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.

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