# [Solved] Type: cannot perform reduce with flexible type

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Type: cannot perform reduce with flexible type in python. So Here I am Explain to you all the possible solutions here.

## How Type: cannot perform reduce with flexible type Error Occurs?

Today I get the following error Type: cannot perform reduce with flexible type in python.

## How To Solve Type: cannot perform reduce with flexible type Error ?

1. How To Solve Type: cannot perform reduce with flexible type Error ?

To Solve Type: cannot perform reduce with flexible type Error Summing by row is just as easy but you will notice that I didn't use this syntax but a slightly different one to avoid the error message

2. Type: cannot perform reduce with flexible type

To Solve Type: cannot perform reduce with flexible type Error Summing by row is just as easy but you will notice that I didn't use this syntax but a slightly different one to avoid the error message

## Solution 1

Consider using Pandas module:

```import pandas as pd

```

Resulting DataFrame:

```In [196]: df
Out[196]:
Game1  Game2  Game3  Game4  Game5
Player1      2      6      5      2      2
Player2      6      4      1      8      4
Player3      8      3      2      1      5
Player4      4      9      4      7      9
```

Sum:

```In [197]: df.sum(axis=1)
Out[197]:
Player1    17
Player2    23
Player3    19
Player4    33
dtype: int64

In [198]: df.sum(1).values
Out[198]: array([17, 23, 19, 33], dtype=int64)
```

## Solution 2

You can still use a structured array as long as you familiarize yourself with the dtypes. Since your data set is extremely small, the following may serve as an example of using numpy in conjunction with list comprehensions when your dtype is uniform but named

```dt = [('Game1', '<i4'), ('Game2', '<i4'), ('Game3', '<i4'),
('Game4', '<i4'), ('Game5', '<i4')]
a = np.array([(2, 6, 5, 2, 2),
(6, 4, 1, 8, 4),
(8, 3, 2, 1, 5),
(4, 9, 4, 7, 9)], dtype= dt)

nms = a.dtype.names
by_col = [(i, a[i].sum()) for i in nms if a[i].dtype.kind in ('i', 'f')]
by_col
[('Game1', 20), ('Game2', 22), ('Game3', 12), ('Game4', 18), ('Game5', 20)]

by_row = [("player {}".format(i), sum(a[i])) for i in range(a.shape[0])]
by_row
[('player 0', 17), ('player 1', 23), ('player 2', 19), ('player 3', 33)]
```

In this example, it would be a real pain to get each sum individually for each column name. That is where the … a[i] for i in nms bit is useful since the list of names was retrieved by nms = a.dtype.names. Since you are doing a ‘sum’ then you want to restrict the summation to only integer and float types, hence the a[i].dtype.kind portion.

Summing by row is just as easy but you will notice that I didn’t use this syntax but a slightly different one to avoid the error message

```a[0].sum()  # massive failure
....snip out huge error stuff...
TypeError: cannot perform reduce with flexible type
# whereas, this works....
sum(a[0])   # use list/tuple summation
```

Perhaps ‘flexible’ data types don’t live up to their name. So you can still work with structured and recarrays if that is the way that your data comes in. You can become adept at simply reformatting your data by slicing and altering dtypes to suit your purpose. For example, since your data type are all the same and you don’t have a monstrous dataset, then you can use many methods to convert to a simple structured array.

```b = np.array([list(a[i]) for i in range(a.shape[0])])
b
array([[2, 6, 5, 2, 2],
[6, 4, 1, 8, 4],
[8, 3, 2, 1, 5],
[4, 9, 4, 7, 9]])

b.sum(axis=0)
array([20, 22, 12, 18, 20])

b.sum(axis=1)
array([17, 23, 19, 33])
```

So you have many options when dealing with structured arrays and depending on whether you need to work in pure python, numpy, pandas or a hybrid, then you should familiarize yourself with all the options.

As a shortcut, I failed to mention taking ‘views’ of arrays that are structured in nature, but have the same dtype. In the above case, a simple way to produce the requirements for simple array calculations by row or column are as follows… a copy of the array was made, but not necessary

```b = a.view(np.int32).reshape(len(a), -1)
b
array([[2, 6, 5, 2, 2],
[6, 4, 1, 8, 4],
[8, 3, 2, 1, 5],
[4, 9, 4, 7, 9]])
b.dtype
dtype('int32')

b.sum(axis=0)
array([20, 22, 12, 18, 20])

b.sum(axis=1)
array([17, 23, 19, 33])```

## Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.