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[Solved] TypeError: ‘int’ object is not callable

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error TypeError: ‘int’ object is not callable in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How TypeError: ‘int’ object is not callable Error Occurs?

Today I get the following error TypeError: ‘int’ object is not callable in python.

How To Solve TypeError: ‘int’ object is not callable Error ?

  1. How To Solve TypeError: 'int' object is not callable Error ?

    To Solve TypeError: 'int' object is not callable Error Somewhere else in your code you have something that looks like this:

  2. TypeError: 'int' object is not callable

    To Solve TypeError: 'int' object is not callable Error Somewhere else in your code you have something that looks like this:

Solution 1

I got the same error (TypeError: ‘int’ object is not callable)

def xlim(i,k,s1,s2):
   x=i/(2*k)
   xl=x*(1-s2*x-s1*(1-x)) / (1-s2*x**2-2*s1*x(1-x))
   return xl 
... ... ... ... 

>>> xlim(1,100,0,0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in xlim
TypeError: 'int' object is not callable

after reading this post I realized that I forgot a multiplication sign * so

def xlim(i,k,s1,s2):
   x=i/(2*k)
   xl=x*(1-s2*x-s1*(1-x)) / (1-s2*x**2-2*s1*x * (1-x))
   return xl 

xlim(1.0,100.0,0.0,0.0)
0.005

tanks

Solution 2

Somewhere else in your code you have something that looks like this:

round = 42

Then when you write

round((a/b)*0.9*c)

that is interpreted as meaning a function call on the object bound to round, which is an int. And that fails.

The problem is whatever code binds an int to the name round. Find that and remove it.

Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.

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