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[Solved] Value: dictionary update sequence element #0 has length 1; 2 is required

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Value: dictionary update sequence element #0 has length 1; 2 is required in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Value: dictionary update sequence element #0 has length 1; 2 is required Error Occurs?

Today I get the following error Value: dictionary update sequence element #0 has length 1; 2 is required in python.

How To Solve Value: dictionary update sequence element #0 has length 1; 2 is required Error ?

  1. How To Solve Value: dictionary update sequence element #0 has length 1; 2 is required Error ?

    To Solve Value: dictionary update sequence element #0 has length 1; 2 is required Error I don't know if it's the same thing that hit your code, but for me the root cause was because I forgot to put name= on the last argument of the url (or path in Django 2.0+) function call.

  2. Value: dictionary update sequence element #0 has length 1; 2 is required

    To Solve Value: dictionary update sequence element #0 has length 1; 2 is required Error I don't know if it's the same thing that hit your code, but for me the root cause was because I forgot to put name= on the last argument of the url (or path in Django 2.0+) function call.

Solution 1

Just ran into this problem. I don’t know if it’s the same thing that hit your code, but for me the root cause was because I forgot to put name= on the last argument of the url (or path in Django 2.0+) function call.

For instance, the following functions throw the error from the question:

url(r'^foo/(?P<bar>[A-Za-z]+)/$', views.FooBar.as_view(), 'foo')
path('foo/{slug:bar}/', views.FooBar, 'foo')

But these actually work:

url(r'^foo/(?P<bar>[A-Za-z]+)/$', views.FooBar.as_view(), name='foo')
path('foo/{slug:bar}/', views.FooBar, name='foo')

The reason why the traceback is unhelpful is because internally, Django wants to parse the given positional argument as the keyword argument kwargs, and since a string is an iterable, an atypical code path begins to unfold. Always use name= on your urls!

Solution 2

I got this error when I was messing around with string and dictionary.

dict1 = {'taras': 'vaskiv', 'iruna': 'vaskiv'}
str1 = str(dict1)
dict(str1)
*** ValueError: dictionary update sequence element #0 has length 1; 2 is required

So what you actually got to do to get dict from string is:

dic2 = eval(str1)
dic2
{'taras': 'vaskiv', 'iruna': 'vaskiv'}

Or in matter of security we can use literal_eval

from ast import literal_eval

Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you? Thank You.

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