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[Solved] Why does this iterative list-growing code give IndexError: list assignment index out of range?

Hello Guys, How are you all? Hope You all Are Fine. Today I get the following error Why does this iterative list-growing code give IndexError: list assignment index out of range? in python. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Why does this iterative list-growing code give IndexError: list assignment index out of range Error Occurs?

Today I get the following error Why does this iterative list-growing code give IndexError: list assignment index out of range? in python.

How To Solve Why does this iterative list-growing code give IndexError: list assignment index out of range Error ?

  1. How To Solve Why does this iterative list-growing code give IndexError: list assignment index out of range Error ?

    To Solve Why does this iterative list-growing code give IndexError: list assignment index out of range Error j is an empty list, but you're attempting to write to element [0] in the first iteration, which doesn't exist yet.

  2. Why does this iterative list-growing code give IndexError: list assignment index out of range?

    To Solve Why does this iterative list-growing code give IndexError: list assignment index out of range Error j is an empty list, but you're attempting to write to element [0] in the first iteration, which doesn't exist yet.

Solution 1

I think the Python method insert is what you’re looking for:

Inserts element x at position i. list.insert(i,x)

array = [1,2,3,4,5]
# array.insert(index, element)
array.insert(1,20)

print(array)

# prints [1,20,2,3,4,5]

Solution 2


j
 is an empty list, but you’re attempting to write to element [0] in the first iteration, which doesn’t exist yet.

Try the following instead, to add a new element to the end of the list:

for l in i:
    j.append(l)

Of course, you’d never do this in practice if all you wanted to do was to copy an existing list. You’d just do:

j = list(i)

Alternatively, if you wanted to use the Python list like an array in other languages, then you could pre-create a list with its elements set to a null value (None in the example below), and later, overwrite the values in specific positions:

i = [1, 2, 3, 5, 8, 13]
j = [None] * len(i)
#j == [None, None, None, None, None, None]
k = 0

for l in i:
   j[k] = l
   k += 1

The thing to realise is that a list object will not allow you to assign a value to an index that doesn’t exist.

Summery

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